刚刚接触，请问怎么写点击某个菜单打开相应文件

ydwinxp

void Player::createMenus()
{
    QMenu *fileMenu = ui->menubar->addMenu("文件(&F)");
    QAction *openAct = new QAction("打开(&O)", this);
    openAct->setShortcut(QKeySequence::Open);
    openAct->setStatusTip("打开媒体文件");
    connect(openAct, &QAction::triggered, this, &Player::openFile);

    QAction *addToPlaylistAct = new QAction("添加到播放列表(&A)", this);
    connect(addToPlaylistAct, &QAction::triggered, this, &Player::addToPlaylist);

    QAction *removeFromPlaylistAct = new QAction("从播放列表移除(&R)", this);
    connect(removeFromPlaylistAct, &QAction::triggered, this, &Player::removeFromPlaylist);

    QAction *savePlaylistAct = new QAction("保存播放列表(&S)", this);
    connect(savePlaylistAct, &QAction::triggered, this, &Player::savePlaylist);

    QAction *loadPlaylistAct = new QAction("加载播放列表(&L)", this);
    connect(loadPlaylistAct, &QAction::triggered, this, &Player::loadPlaylist);

    QAction *openLocalFileAction = new QAction("打开第一课", this);

  这里点打开第一课，怎么能实现打开程序目录下1.mp4
    fileMenu->addAction(openLocalFileAction);